1.0.0[−][src]Function std::ptr::replace
pub unsafe fn replace<T>(dst: *mut T, src: T) -> T
Moves src
into the pointed dst
, returning the previous dst
value.
Neither value is dropped.
This function is semantically equivalent to mem::replace
except that it
operates on raw pointers instead of references. When references are
available, mem::replace
should be preferred.
Safety
Behavior is undefined if any of the following conditions are violated:
-
dst
must be valid for writes. -
dst
must be properly aligned.
Note that even if T
has size 0
, the pointer must be non-NULL and properly aligned.
Examples
use std::ptr; let mut rust = vec!['b', 'u', 's', 't']; // `mem::replace` would have the same effect without requiring the unsafe // block. let b = unsafe { ptr::replace(&mut rust[0], 'r') }; assert_eq!(b, 'b'); assert_eq!(rust, &['r', 'u', 's', 't']);Run